6x^2+7(2^(1/2))x+4=0

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Solution for 6x^2+7(2^(1/2))x+4=0 equation: 


x in (-oo:+oo)

6*x^2+7*2^(1/2)*x+4 = 0

6*x^2+7*2^(1/2)*x+4 = 0

DELTA = (7*2^(1/2))^2-(4*4*6)

DELTA = 2

DELTA > 0

x = (2^(1/2)-(7*2^(1/2)))/(2*6) or x = (-(7*2^(1/2))-2^(1/2))/(2*6)

x = (-2^(1/2))/2 or x = (-7*2^(1/2)-2^(1/2))/12

x in { (-7*2^(1/2)-2^(1/2))/12, (-2^(1/2))/2 }

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